2000 XRA, A AF Clear register A
2001 MVI B, 32 06 Load in Reg. B the no. whose parity is to be checked(32)
2003 MVI C,00 0E Initialize Reg. C
2005 ADD B 80 Perform an operation so that the flags are affected
2006 JPO 200A E2 Jump if Parity is Odd to Address 200A
2009 INR C 0C Increment C if Parity is Even
200A MOV A, C 79 Move the content of C in Accumulator
200B STA 2050 32 Store the result in Address 2050H
200E HLT 76
The above Program would store 1 at 2050H mem. Addr. If the Parity is Even and 0 if the parity is odd. In the above case we have taken the no. to be 32 which is (100000) in binary, hence has odd parity. Note: Parity is the number of 1’s in the circuit.
Input: (52)10 =(110100)2
Output: 0 (as it has odd no. of 1’s i.e. Odd Parity)
PhD researcher at Friedrich-Schiller University Jena, Germany. I’m a physicist specializing in computational material science. I write efficient codes for simulating light-matter interactions at atomic scales. I like to develop Physics, DFT and Machine Learning related apps and softwares from time to time. Can code in most of the popular languages. Like to share my knowledge in Physics and applications using this Blog and a YouTube channel.